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The table above shows the scores of 6 students in Mathematics, in asce
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30 Jul 2023, 23:37
30 Jul 2023, 23:37
Expert Reply
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45% (02:24) correct
54% (02:38) wrong based on 33 sessions
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The table above shows the scores of 6 students in Mathematics, in ascending order. If all the scores are integers and the average of all 6 scores mentioned in the table is 16, then, what is the difference between the scores of Lomb and Tom?
Indicate all that apply
A. 1
B. 3
C. 5
D. 7
E. 9
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Re: The table above shows the scores of 6 students in Mathematics, in asce
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17 Sep 2023, 01:41
17 Sep 2023, 01:41
Expert Reply
OE
We have 10, 13, ๐ฅ, 16, ๐ฆ, 26.
Sum = Average ร Number of terms
So, we have,
(10 + 13 + ๐ฅ + 16 + ๐ฆ + 26) = 16 ร 6
๐ฅ + ๐ฆ = 31
As all the scores are in ascending order, value of ๐ฅ would be from 13 to 16.
Similarly, the value of ๐ฆ would be from 16 to 26.
Values of ๐ฅ and ๐ฆ would be in the mentioned range, and their summation should be 31.
If ๐ฅ = 13, ๐ฆ must be 18. (difference is 5)
If ๐ฅ = 14, ๐ฆ must be 17. (difference is 3)
If ๐ฅ = 15, ๐ฆ must be 16. (difference is 1)
Ans. (A, B and C)
We have 10, 13, ๐ฅ, 16, ๐ฆ, 26.
Sum = Average ร Number of terms
So, we have,
(10 + 13 + ๐ฅ + 16 + ๐ฆ + 26) = 16 ร 6
๐ฅ + ๐ฆ = 31
As all the scores are in ascending order, value of ๐ฅ would be from 13 to 16.
Similarly, the value of ๐ฆ would be from 16 to 26.
Values of ๐ฅ and ๐ฆ would be in the mentioned range, and their summation should be 31.
If ๐ฅ = 13, ๐ฆ must be 18. (difference is 5)
If ๐ฅ = 14, ๐ฆ must be 17. (difference is 3)
If ๐ฅ = 15, ๐ฆ must be 16. (difference is 1)
Ans. (A, B and C)
Re: The table above shows the scores of 6 students in Mathematics, in asce
[#permalink]
26 Aug 2025, 05:00
26 Aug 2025, 05:00
How are you assuming X = 13 and Y = 16 as well? I can very well assume that X = 14 and 15 only and 17<Y<25? It is not clear from the question that X can take 13 also as a possible value and 16 is a possible value for Y as well, given that the question states they are in ascending order?
Carcass wrote:
OE
We have 10, 13, x, 16, y, 26.
Sum = Average ร Number of terms
So, we have,
(10 + 13 + x + 16 + y + 26) = 16 ร 6
x + y = 31
As all the scores are in ascending order, value of x would be from 13 to 16.
Similarly, the value of y would be from 16 to 26.
Values of x and y would be in the mentioned range, and their summation should be 31.
If x = 13, y must be 18. (difference is 5)
If x = 14, y must be 17. (difference is 3)
If x = 15, y must be 16. (difference is 1)
Ans. (A, B and C)
We have 10, 13, x, 16, y, 26.
Sum = Average ร Number of terms
So, we have,
(10 + 13 + x + 16 + y + 26) = 16 ร 6
x + y = 31
As all the scores are in ascending order, value of x would be from 13 to 16.
Similarly, the value of y would be from 16 to 26.
Values of x and y would be in the mentioned range, and their summation should be 31.
If x = 13, y must be 18. (difference is 5)
If x = 14, y must be 17. (difference is 3)
If x = 15, y must be 16. (difference is 1)
Ans. (A, B and C)
