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No line segment with endpoints on the circle with center O i
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24 Nov 2020, 08:26
24 Nov 2020, 08:26
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74% (02:31) correct
25% (01:49) wrong based on 31 sessions
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No line segment with endpoints on the circle with center O is longer than line segment AD.
\(OB = AB=3\)
Quantity A |
Quantity B |
The area of sector OBCD |
9 |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Re: No line segment with endpoints on the circle with center O i
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25 Nov 2020, 00:35
25 Nov 2020, 00:35
1
It is obvious that AD is the diameter of the circle.
OB=AB=OA= radius=3 => OAB is a equilateral triangle
<AOB=60 degree
therefore the area of the sector OBCD= 1/2* area of the circle - area of the sector OAB (which constitute 60 degrees at the center)
= 1/2* pi * 3^2- 60/360 * pi * 3^2
= 14.13- 4.71 = 9.42 (greater than 9)
So A is the answer.
OB=AB=OA= radius=3 => OAB is a equilateral triangle
<AOB=60 degree
therefore the area of the sector OBCD= 1/2* area of the circle - area of the sector OAB (which constitute 60 degrees at the center)
= 1/2* pi * 3^2- 60/360 * pi * 3^2
= 14.13- 4.71 = 9.42 (greater than 9)
So A is the answer.
Re: No line segment with endpoints on the circle with center O i
[#permalink]
16 Oct 2025, 02:02
16 Oct 2025, 02:02
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