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Re: Exactly 8 years ago, Jim’s son was twice as old as Jim’s [#permalink]
Bunuel wrote:
Exactly 8 years ago, Jim’s son was twice as old as Jim’s daughter. If Jim’s son is now 5 years older than his daughter, how old is Jim’s daughter now?

(A) 5
(B) 10
(C) 13
(D) 16
(E) 18

Kudos for correct solution.


Jim’s son is now 5 years older than his daughter
Let D = the daughter's age NOW
So D + 5 = the son's age NOW

This also means that D - 8 = the daughter's age EIGHT YEARS AGO
This also means that D + 5 - 8 = the son's age EIGHT YEARS AGO
Or we can say, D - 3 = the son's age EIGHT YEARS AGO

8 years ago, Jim’s son was twice as old as Jim’s daughter.
8 years ago, the daughter's age was D - 8 and the son's age was D - 3
So, we can write: D - 3 = 2(D - 8)
Expand right side to get: D - 3 = 2D - 16
Solve to get D = 13

Since D = the daughter's present age, the correct answer is C

Cheers,
Brent
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Re: Exactly 8 years ago, Jim’s son was twice as old as Jim’s [#permalink]
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