GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
In a research and development department
[#permalink]
18 Jan 2018, 00:18
18 Jan 2018, 00:18
2
1
00:00
Question Stats:
69% (03:13) correct
30% (03:10) wrong based on 85 sessions
Hide Show timer Statistics
In a research and development department, 14 workers have a PhD, and 30 workers don't have a PhD degree. In the department, the number of women that do not have a PhD degree is 10 greater than the number of women who do have a PhD. If a third of the men working in the department have a PhD degree, then how many women work in the department?
A) 16
B) 18
C) 26
D) 28
E) 32
A) 16
B) 18
C) 26
D) 28
E) 32
Re: In a research and development department
[#permalink]
18 Jan 2018, 20:41
18 Jan 2018, 20:41
2
let us suppose total number of men working in the department is m
and total number of women working in the department is w
Of the total women working in the department let us assume those that have a phd is A
hence those that do not have a phd = A+10
we are given 1/3 M have phd
hence 2/3 M do not have a phd
we have 1/3 M + A = 14 (those with phd).....i
and 2/3 M + A+10 = 30 >> 2/3 M + A = 20 (those without phd)...ii
subtracting eqn i from ii we get,
1/3 M = 6 hence, M = 18
Total number of people that work in the department = 44
Total number of Men that work in the department = 18
hence, total number of women working in the department = 44-18 = 26
(c)
and total number of women working in the department is w
Of the total women working in the department let us assume those that have a phd is A
hence those that do not have a phd = A+10
we are given 1/3 M have phd
hence 2/3 M do not have a phd
we have 1/3 M + A = 14 (those with phd).....i
and 2/3 M + A+10 = 30 >> 2/3 M + A = 20 (those without phd)...ii
subtracting eqn i from ii we get,
1/3 M = 6 hence, M = 18
Total number of people that work in the department = 44
Total number of Men that work in the department = 18
hence, total number of women working in the department = 44-18 = 26
(c)
Re: In a research and development department
[#permalink]
16 Dec 2018, 21:03
16 Dec 2018, 21:03
2
amorphous wrote:
In a research and development department, 14 workers have a PhD, and 30 workers don't have a PhD degree. In the department, the number of women that do not have a PhD degree is 10 greater than the number of women who do have a PhD. If a third of the men working in the department have a PhD degree, then how many women work in the department?
A) 16
B) 18
C) 26
D) 28
E) 32
A) 16
B) 18
C) 26
D) 28
E) 32
Let's use the double matrix method. We will use W for women, M for men, and T for total.
Total number who have PhDs is 14 so we put that in the bottom left. Total number with no PhD is 30 so bottom middle. Total of course should add to 44.
"In the department, the number of women that do not have a PhD degree is 10 greater than the number of women who do have a PhD," thus, we will denote number of women with PhD as X and # of women with no PhD as 10+x.
"If a third of the men working in the department have a PhD degree," so we will denote total number of men with y, then we should put y/3 accordingly for men with PhDs, which leaves 2y/3 for men without phDs.
| PhD | No PhD | T
W | x | 10+x | 2x+ 10
M | y/3 | 2/3y | y
T | 14 | 30 | 44
Now we have a system of linear equations that we need to solve.
x+ 2/3 y = 20
x + y/3 = 14
Upon solving, we get y/3 = 6. We don't need to simplify that, go ahead and plug that in the table.
| PhD | No PhD | T
W | x | 10+x | 2x+ 10
M | 6 | 2/3y | y
T | 14 | 30 | 44
Thus, x = 8.
Then the total number of women is 8 + 18 = 26.
C
