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Re: xy < 0 [#permalink]
Answer: B
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Re: xy < 0 [#permalink]
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It's not a hard question.

Simply, the product of two numbers is negative, so one must be negative and other one must be positive.
Therefore, combined mode will always be less than the sum of individual modes.

Choice B correct.
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Re: xy < 0 [#permalink]
IlCreatore wrote:
This is the so called triangular inequality which states that \(|x+y|\leq|x|+|y|\). Thus, the answer is B or C.

Since xy < 0 it must be that either x or y are negative. Thus, in this case it is impossible to have an equality for whatever number we fit in the equation. E.g. x = 1, y = -2; then, \(|1-2|\leq|1|+|-2|\) which becomes \(1<3\).

Thus, the answer is B


never heard of this inequality, where have you seen in featured before?
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Re: xy < 0 [#permalink]
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Not a 'hard' category question.
LHS = |x + y| = when I remove abs value, it can be - x - y = -ve value or x + y = +ve value and xy < 0 [so one of them is -ve]
RHS = |x| + |y| = always a +ve value despite one of the no's being -ve. So B is greater

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Re: xy < 0 [#permalink]
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Re: xy < 0 [#permalink]
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