Last visit was: 22 Nov 2024, 02:46 It is currently 22 Nov 2024, 02:46

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
Verbal Expert
Joined: 18 Apr 2015
Posts: 30003
Own Kudos [?]: 36348 [5]
Given Kudos: 25927
Send PM
avatar
Director
Director
Joined: 03 Sep 2017
Posts: 518
Own Kudos [?]: 703 [0]
Given Kudos: 0
Send PM
avatar
Intern
Intern
Joined: 08 Dec 2017
Posts: 40
Own Kudos [?]: 69 [3]
Given Kudos: 0
Send PM
avatar
Intern
Intern
Joined: 07 Feb 2018
Posts: 13
Own Kudos [?]: 2 [0]
Given Kudos: 0
Send PM
Re: xy < 0 [#permalink]
Answer: B
avatar
Intern
Intern
Joined: 11 Jan 2018
Posts: 44
Own Kudos [?]: 104 [3]
Given Kudos: 0
Send PM
Re: xy < 0 [#permalink]
3
It's not a hard question.

Simply, the product of two numbers is negative, so one must be negative and other one must be positive.
Therefore, combined mode will always be less than the sum of individual modes.

Choice B correct.
avatar
Intern
Intern
Joined: 17 Feb 2018
Posts: 9
Own Kudos [?]: 2 [0]
Given Kudos: 0
Send PM
Re: xy < 0 [#permalink]
IlCreatore wrote:
This is the so called triangular inequality which states that \(|x+y|\leq|x|+|y|\). Thus, the answer is B or C.

Since xy < 0 it must be that either x or y are negative. Thus, in this case it is impossible to have an equality for whatever number we fit in the equation. E.g. x = 1, y = -2; then, \(|1-2|\leq|1|+|-2|\) which becomes \(1<3\).

Thus, the answer is B


never heard of this inequality, where have you seen in featured before?
avatar
Manager
Manager
Joined: 19 Mar 2018
Posts: 64
Own Kudos [?]: 37 [0]
Given Kudos: 0
Send PM
Re: xy < 0 [#permalink]
1
Not a 'hard' category question.
LHS = |x + y| = when I remove abs value, it can be - x - y = -ve value or x + y = +ve value and xy < 0 [so one of them is -ve]
RHS = |x| + |y| = always a +ve value despite one of the no's being -ve. So B is greater

Kudos if you like this answer
User avatar
GRE Prep Club Legend
GRE Prep Club Legend
Joined: 07 Jan 2021
Posts: 5034
Own Kudos [?]: 74 [0]
Given Kudos: 0
Send PM
Re: xy < 0 [#permalink]
Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Prep Club for GRE Bot
Re: xy < 0 [#permalink]
Moderators:
GRE Instructor
84 posts
GRE Forum Moderator
37 posts
Moderator
1111 posts
GRE Instructor
234 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne