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Re: Figure shown below consists of two squares having [#permalink]
B

The outer square's side will get divided in 3 sections of length 4 each. This will make a right triangle at the corners, with base and perpendicular sides of length 4 each, so the hypotenuse will be 4 root 2.
Quantity A: - Perimeter = 4 + 4 root 2 + 12 + 4 root 2 = 16 + 8 root 2 = 27.3
Quantity B:- Area (this becomes a trapezium) = height * (average of sum of lengths of parallel sides) = 4 * {(12 + 4)/ 2} = 4 * 8 = 32
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Re: Figure shown below consists of two squares having [#permalink]
B but did with diagonal.
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Re: Figure shown below consists of two squares having [#permalink]
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