sandy wrote:
In the history class that consisted of 30 students, the number of seniors was 3 more than twice the number of juniors, and 3/10 of the students were neither juniors nor seniors
Column A: The number of juniors in the class
Column B: 6
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Let J = number of juniors in the class
Let S = number of seniors in the class
3/10 of the 30 students were neither juniors nor seniorsSo, 7/10 were either juniors or seniors
7/10 of 30 = 21.
We can write:
J + S = 21...the number of seniors was 3 more than twice the number of juniorsWe can write:
S = 2J + 3We now have the following system of equations:
J + S = 21S = 2J + 3Take the top equation and replace S with 2J + 3 to get; J + (2J + 3) = 21
Simplify: 3J + 3 = 21
Solve: J = 6
So, we get:
Quantity A: 6
Quantity B: 6
Answer: C
Cheers,
Brent