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GRE Math Challenge #29-On a turntable, a record

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sandy
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GRE Math Challenge #29-On a turntable, a record [#permalink] New post   Updated on: 15 Apr 2020, 07:55
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On a turntable, a record of radius 6 inches is rotating at the rate of 45 revolutions per minute.


Quantity A
Quantity B
The number of inches traveled per minute by a point on the circumference of the record
The number of inches traveled per minute by a point on the record 5 inches from the center of the record



A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
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A

Originally posted by sandy on 19 Sep 2014, 02:54.
Last edited by Carcass on 15 Apr 2020, 07:55, edited 1 time in total.
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Peter
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Re: GRE Math Challenge #29-On a turntable, a record [#permalink] New post   11 Mar 2018, 04:54
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sandy wrote:
On a turntable, a record of radius 6 inches is rotating at the rate of 45 revolutions per minute.

Column A: The number of inches traveled per minute by a point on the circumference of the record
Column B: The number of inches traveled per minute by a point on the record 5 inches from the center of the record

A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.


For this question, we should know that one revolution is 360 degrees.

Then, for Quant A, the The number of inches traveled per minute by a point on the circumference of the record would be 12(=6*2)*pi*45=540pi

For Quant B, The number of inches traveled per minute by a point on the record 5 inches from the center of the record would be 10(=5*2)*pi*45= 450pi.

Hence, B>A
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gmatclubot
Re: GRE Math Challenge #29-On a turntable, a record [#permalink]
11 Mar 2018, 04:54
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