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Jane scored in the 68th percentile on a test, and John score
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Updated on: 06 Apr 2018, 07:53
Updated on: 06 Apr 2018, 07:53
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52% (00:48) correct
47% (00:54) wrong based on 48 sessions
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Jane scored in the 68th percentile on a test, and John scored in the 32nd percentile.
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The proportion of the class that received a score less than John's score |
The proportion of the class that scored equal to or greater than Jane's score |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Re: Jane scored in the 68th percentile on a test, and John score
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06 Apr 2018, 07:56
06 Apr 2018, 07:56
Expert Reply
my solving
but what I thought is that if there are 100 people, and score is distributed normally(1 to 100)
John's score is 32. so less than 32 is 31(31 people)
Jane's score is 68. so equal to or greater than 68 is 32(32 people with Jane)
than Quantity can be greater, but what's the problem of my solving?
this is answer from book.
Percentiles define the proportion of a group that scores below a particular benchmark. Since John scored in the 32nd percentile, by definition, 32% of the class scored worse than John. Quantity A is equal to 32%
Jane scored in the 68th percentile, so 68% of the class scored worse than she did. Since 100 - 68 = 32, 32% of the class scored equal to or greater than Jane. Quantity B is also equal to 32%
official answer is C (so Quantity A is equal to Quantity B)
but what I thought is that if there are 100 people, and score is distributed normally(1 to 100)
John's score is 32. so less than 32 is 31(31 people)
Jane's score is 68. so equal to or greater than 68 is 32(32 people with Jane)
than Quantity can be greater, but what's the problem of my solving?
this is answer from book.
Percentiles define the proportion of a group that scores below a particular benchmark. Since John scored in the 32nd percentile, by definition, 32% of the class scored worse than John. Quantity A is equal to 32%
Jane scored in the 68th percentile, so 68% of the class scored worse than she did. Since 100 - 68 = 32, 32% of the class scored equal to or greater than Jane. Quantity B is also equal to 32%
official answer is C (so Quantity A is equal to Quantity B)
Re: Jane scored in the 68th percentile on a test, and John score
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06 Apr 2018, 08:05
06 Apr 2018, 08:05
Expert Reply
Please follow the rules for posting on the board
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Regards
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https://gre.myprepclub.com/forum/rules-for ... -1083.html
Ask for further assistance or questions regarding your post
Regards
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