GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
If n is a positive integer, which one of the following numbe
[#permalink]
21 Apr 2018, 05:00
21 Apr 2018, 05:00
Expert Reply
2
Bookmarks
00:00
Question Stats:
76% (02:08) correct
23% (01:58) wrong based on 34 sessions
Hide Show timer Statistics
If n is a positive integer, which one of the following numbers must have a remainder of 3 when divided by any of the numbers 4, 5, and 6?
(A) 12n + 3
(B) 24n + 3
(C) 80n + 3
(D) 90n + 2
(E) 120n + 3
(A) 12n + 3
(B) 24n + 3
(C) 80n + 3
(D) 90n + 2
(E) 120n + 3
Re: If n is a positive integer, which one of the following numbe
[#permalink]
21 Apr 2018, 21:41
21 Apr 2018, 21:41
2
The number sould have 4, 5 and 6 as common factors. So the answer would be E. +3 is common as that is expected as remainder.
Re: If n is a positive integer, which one of the following numbe
[#permalink]
26 Apr 2018, 09:16
26 Apr 2018, 09:16
2
The remainder equation can be formed for each of the divisors as follows :-
1.N=4q+3
2.N=5q+3
3.N=6q+3
Now we should be knowing that Least common multiple of 4,5 and 6 is 4*5*6 =120.
So value for each of the equations could be:
1.N=4q+3=123
2.N=5q+3=128
3.N=6q+3=129
Hence when we divide 123,128 and 129 by 4, 5 and 6 respectively then we get 3 as a remainder.
hence option E is the answer.
1.N=4q+3
2.N=5q+3
3.N=6q+3
Now we should be knowing that Least common multiple of 4,5 and 6 is 4*5*6 =120.
So value for each of the equations could be:
1.N=4q+3=123
2.N=5q+3=128
3.N=6q+3=129
Hence when we divide 123,128 and 129 by 4, 5 and 6 respectively then we get 3 as a remainder.
hence option E is the answer.
