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Re: Child A ate 3/5 of a kilogram of chocolate and Child B ate 3 [#permalink]
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A= (3/5)*1000=600
B=2*300 =600
hence answer C
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Re: Child A ate 3/5 of a kilogram of chocolate and Child B ate 3 [#permalink]
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Arc29 wrote:
A= (3/5)*1000=600
B=2*300 =600
hence answer C


instead of (3/5)*1000=600
my friend what you can do is just multiply 2 on both numerator and denominator so its becomes easier to estimate the percentage hence easy to determine the weight.
it would be 6/10 which is 60% so 600 grams.
just make denominator either 10, 100 or as close to 100 as possible so you can take an approximation
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Re: Child A ate 3/5 of a kilogram of chocolate and Child B ate 3 [#permalink]
sandy wrote:
Child A ate \(\frac{3}{5}\) of a kilogram of chocolate and Child B ate 300 grams of chocolate. (1kilogram = 1000 grams)

Quantity A
Quantity B
The weight, in grams, of the chocolate that Child A ate
Twice the weight, in grams, of the chocolate that Child B ate


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.


My stupid ass completely ignored the Quantity B twice the gram
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Re: Child A ate 3/5 of a kilogram of chocolate and Child B ate 3 [#permalink]
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