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Randall purchased a shirt for $19.44 using a $20 bill. If
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27 May 2018, 03:59
27 May 2018, 03:59
Expert Reply
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Question Stats:
63% (01:43) correct
36% (01:40) wrong based on 60 sessions
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Randall purchased a shirt for $19.44 using a $20 bill. If his correct change was returned in only dimes ($0.10) and pennies ($0.01), how many coins could Randall have received?
(A) 9
(B) 21
(C) 29
(D) 37
(E) 44
(A) 9
(B) 21
(C) 29
(D) 37
(E) 44
Re: Randall purchased a shirt for $19.44 using a $20 bill. If
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27 May 2018, 13:21
27 May 2018, 13:21
1
Expert Reply
Explanation
From the first sentence, calculate Randall’s change (20.00 – 19.44 = 0.56). Then it’s a matter of systematic tests to determine the various combinations of dimes and pennies that Randall could have received, stopping when one matches an answer choice listed:
5 dimes (0.50) + 6 pennies (0.06) = 11 coins Not an option in the choices
4 dimes (0.40) + 16 pennies (0.16) = 20 coins Not an option in the choices
3 dimes (0.30) + 26 pennies (0.26) = 29 coins Correct answer
Hence option C is correct!
From the first sentence, calculate Randall’s change (20.00 – 19.44 = 0.56). Then it’s a matter of systematic tests to determine the various combinations of dimes and pennies that Randall could have received, stopping when one matches an answer choice listed:
5 dimes (0.50) + 6 pennies (0.06) = 11 coins Not an option in the choices
4 dimes (0.40) + 16 pennies (0.16) = 20 coins Not an option in the choices
3 dimes (0.30) + 26 pennies (0.26) = 29 coins Correct answer
Hence option C is correct!
Re: Randall purchased a shirt for $19.44 using a $20 bill. If
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20 Jun 2023, 10:25
20 Jun 2023, 10:25
First convert everything to cents:
$20=2000 cents
$19.44=1944 cents
the change will be:
2000-1944=56
56=10d+1p
Now just check all possible combinations:
d=0, p=56 -> 56 coins (not an option)
d=1, p=46 -> 48 coins (not an option)
d=2, p=36 -> 38 coins (not an option)
d=3, p=26 -> 29 coins (option C)
d=4, p= 16 -> 20 coins (not an option)
d=5, p=6 -> 11 coins (not an option.
Out of all the cases, only C is available.
As a general strategy, it is useful to write all of the possibilities because you may have missed a restriction in the question - so if you get more than one option, it might be good to revisit the question stem.
$20=2000 cents
$19.44=1944 cents
the change will be:
2000-1944=56
56=10d+1p
Now just check all possible combinations:
d=0, p=56 -> 56 coins (not an option)
d=1, p=46 -> 48 coins (not an option)
d=2, p=36 -> 38 coins (not an option)
d=3, p=26 -> 29 coins (option C)
d=4, p= 16 -> 20 coins (not an option)
d=5, p=6 -> 11 coins (not an option.
Out of all the cases, only C is available.
As a general strategy, it is useful to write all of the possibilities because you may have missed a restriction in the question - so if you get more than one option, it might be good to revisit the question stem.
