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Re: The perimeter of a rectangular patio is 268 feet and its le
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27 May 2018, 13:19
Explanation
This rectangle problem requires applying the perimeter and area formulas. The area of a rectangle is equal to length times width (A = LW) and the perimeter is 2L + 2W = 268. The question states that the length equals 168% of the width, L = 1.68W.
2L + 2W = 268
L + W = 134
1.68W + W = 134
2.68W = 134
W = 50
Solve for L by plugging 50 in for W in either equation:
L + 50 = 134
L = 84
A = 84(50) = 4,200
Hence option B is correct!