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The perimeter of a rectangular patio is 268 feet and its le

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sandy
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The perimeter of a rectangular patio is 268 feet and its le [#permalink] New post   27 May 2018, 03:58
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The perimeter of a rectangular patio is 268 feet and its length is 168% of its width. What is the area of the patio, in square feet?

(A) 4,000
(B) 4,200
(C) 4,320
(D) 4,600
(E) 4,760
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B
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sandy
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Re: The perimeter of a rectangular patio is 268 feet and its le [#permalink] New post   27 May 2018, 13:19
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Explanation

This rectangle problem requires applying the perimeter and area formulas. The area of a rectangle is equal to length times width (A = LW) and the perimeter is 2L + 2W = 268. The question states that the length equals 168% of the width, L = 1.68W.

2L + 2W = 268

L + W = 134

1.68W + W = 134

2.68W = 134

W = 50

Solve for L by plugging 50 in for W in either equation:

L + 50 = 134

L = 84

A = 84(50) = 4,200

Hence option B is correct!
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Re: The perimeter of a rectangular patio is 268 feet and its le [#permalink] New post   10 Nov 2019, 21:46
Make use of a proper dimensions before directly implementing the task.
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gmatclubot
Re: The perimeter of a rectangular patio is 268 feet and its le [#permalink]
10 Nov 2019, 21:46
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