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Re: If 12x + 2y is 80% of 5y, what is the value
[#permalink]
14 May 2018, 07:48
GreenlightTestPrep wrote:
If 12x + 2y is 80% of 5y, what is the value of x/y ?
A) 1/6 B) 1/4 C) 2/5 D) 1/2 E) 5/8
GIVEN: 12x + 2y is 80% of 5y Rewrite as: 12x + 2y = (80/100)(5y) Evaluate to get: 12x + 2y = 4y Subtract 2y from both sides of the equation to get: 12x = 2y Divide both sides by y to get: 12x/y = 2 Divide both sides by 12 to get: x/y = 2/12 Simplify: x/y = 1/6
Re: If 12x + 2y is 80% of 5y, what is the value
[#permalink]
01 Jun 2018, 03:23
GreenlightTestPrep wrote:
GreenlightTestPrep wrote:
If 12x + 2y is 80% of 5y, what is the value of x/y ?
A) 1/6 B) 1/4 C) 2/5 D) 1/2 E) 5/8
GIVEN: 12x + 2y is 80% of 5y Rewrite as: 12x + 2y = (80/100)(5y) Evaluate to get: 12x + 2y = 4y Subtract 2y from both sides of the equation to get: 12x = 2y Divide both sides by y to get: 12x/y = 2 Divide both sides by 12 to get: x/y = 2/12 Simplify: x/y = 1/6
Answer: A
Cheers, Brent
Brent I am unable to understand the highlighted , pls elucidate.
Re: If 12x + 2y is 80% of 5y, what is the value
[#permalink]
01 Jun 2018, 05:40
IshanGre wrote:
GreenlightTestPrep wrote:
GreenlightTestPrep wrote:
If 12x + 2y is 80% of 5y, what is the value of x/y ?
A) 1/6 B) 1/4 C) 2/5 D) 1/2 E) 5/8
GIVEN: 12x + 2y is 80% of 5y Rewrite as: 12x + 2y = (80/100)(5y) Evaluate to get: 12x + 2y = 4y Subtract 2y from both sides of the equation to get: 12x = 2y Divide both sides by y to get: 12x/y = 2 Divide both sides by 12 to get: x/y = 2/12 Simplify: x/y = 1/6
Answer: A
Cheers, Brent
Brent I am unable to understand the highlighted , pls elucidate.
Once we know that 12x = 2y, we must determine the value of x/y To do so, we must follow the Golden Rule of Equation Solving: what you do to one side of the equation, you must do to the other side.
So, to move the y to the left side of the equation, I took 12x = 2y and divided BOTH sides by y to get: 12x/y = 2 To move the 12 to the left side, I took 12x/y = 2 and divided BOTH sides by 12 to get: x/y = 2/12