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If y is 4 greater than one-fourth of x,
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25 Jun 2018, 11:58
25 Jun 2018, 11:58
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If y is 4 greater than one-fourth of x, and x ≠ 0, what is the ratio of y to x in terms of x?
A) (x² + 16x)/4
B) (4x + 16)/x
C) (x + 16)/4x
D) (4x + 1)/x
E) (x + 16)/x
A) (x² + 16x)/4
B) (4x + 16)/x
C) (x + 16)/4x
D) (4x + 1)/x
E) (x + 16)/x
Re: If y is 4 greater than one-fourth of x,
[#permalink]
25 Jun 2018, 22:34
25 Jun 2018, 22:34
1
GreenlightTestPrep wrote:
If y is 4 greater than one-fourth of x, and x ≠ 0, what is the ratio of y to x in terms of x?
A) (x² + 16x)/4
B) (4x + 16)/x
C) (x + 16)/4x
D) (4x + 1)/x
E) (x + 16)/x
A) (x² + 16x)/4
B) (4x + 16)/x
C) (x + 16)/4x
D) (4x + 1)/x
E) (x + 16)/x
Here
given y = 4 + \(\frac{x}{4}\)
or y = \(\frac{(16 + x)}{4}\)
Now dividing both side by x we get;
\(\frac{y}{x}\) = \(\frac{(16 + x)}{4x}\)
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Re: If y is 4 greater than one-fourth of x,
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27 Jun 2018, 16:16
27 Jun 2018, 16:16
1
Expert Reply
GreenlightTestPrep wrote:
If y is 4 greater than one-fourth of x, and x ≠ 0, what is the ratio of y to x in terms of x?
A) (x² + 16x)/4
B) (4x + 16)/x
C) (x + 16)/4x
D) (4x + 1)/x
E) (x + 16)/x
A) (x² + 16x)/4
B) (4x + 16)/x
C) (x + 16)/4x
D) (4x + 1)/x
E) (x + 16)/x
We see that y = (1/4)x + 4 = x/4 + 16/4 = (x + 16)/4, so
y/x = [(x + 16)/4]/x = (x + 16)/4x
Answer: C
