Last visit was: 28 Dec 2024, 02:58 It is currently 28 Dec 2024, 02:58
Decision Tracker
My Rewards
New comers' posts
New posts
Unanswered

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Go to My Error Log Learn more
Close

Request Expert Reply

Confirm Cancel
PREVIOUS TOPIC
NEXT TOPIC

Je? and Ali race each other at the Tentleytown Speedway.

Tags :
Find Similar Topics  About  Add a Tag

Show Tags
Hide Tags

User avatar
sandy
Retired Moderator
Joined: 07 Jun 2014
Posts: 4815
Own Kudos [?]: 11277 [4]
Given Kudos: 0
GRE 1: Q167 V156
WE:Business Development (Energy and Utilities)
Send PM
Je? and Ali race each other at the Tentleytown Speedway. [#permalink] New post   08 Dec 2017, 20:56
Expert Reply
4
Bookmarks
00:00

Question Stats:

30% (01:27) correct 70% (01:47) wrong based on 40 sessions

Hide Show timer Statistics

Jeff and Ali race each other at the Tentleytown Speedway. Ali’s car travels at 300 feet per second, and Je?’s car travels at 250 feet per second. If one lap around the track is 3000 feet long, and each car travels at a constant rate, how many laps will it take Ali to overtake Jeff?

A. 1
B. 5
C. 6
D. 10
E. 60

Drill 4
Question: 2
Page: 531
ShowHide Answer
Official Answer
C
User avatar
sandy
Retired Moderator
Joined: 07 Jun 2014
Posts: 4815
Own Kudos [?]: 11277 [3]
Given Kudos: 0
GRE 1: Q167 V156
WE:Business Development (Energy and Utilities)
Send PM
Re: Je? and Ali race each other at the Tentleytown Speedway. [#permalink] New post   29 Dec 2017, 15:39
1
1
Expert Reply
1
Bookmarks
Explanation

Use the Rate Pie.

Ali is traveling 50 feet per second faster than Jeff is traveling. Therefore, that is the rate at which she is effectively gaining ground on him. Put that in the
lower-right segment of the Rate Pie. We want to know how long it will take her to gain 3,000 feet on him.

Put 3,000 in the top section of the Rate Pie. Now you can see that dividing \(\frac{3000}{50}\) will fill in the last segment of the Rate Pie, telling you how long it takes Ali to do so is 60 seconds. Be aware that choice (E) is an incorrect partial answer.

Now you need to find out how many feet Ali will travel in 60 seconds, by multiplying 60 second × 300 feet per second, which equals 18,000 feet. Divide 18,000 feet by the length of one lap, or 3,000 feet, and you’ll find that it will take Ali 6 laps to overtake Jeff.

Hence option C is correct!
avatar
Peter
Manager
Manager
Joined: 27 Sep 2017
Posts: 110
Own Kudos [?]: 82 [0]
Given Kudos: 0
Send PM
Re: Je? and Ali race each other at the Tentleytown Speedway. [#permalink] New post   29 Dec 2017, 22:37
sandy wrote:
Explanation

Use the Rate Pie.

Ali is traveling 50 feet per second faster than Jeff is traveling. Therefore, that is the rate at which she is effectively gaining ground on him. Put that in the
lower-right segment of the Rate Pie. We want to know how long it will take her to gain 3,000 feet on him.

Put 3,000 in the top section of the Rate Pie. Now you can see that dividing \(\frac{3000}{50}\) will fill in the last segment of the Rate Pie, telling you how long it takes Ali to do so is 60 seconds. Be aware that choice (E) is an incorrect partial answer.

Now you need to find out how many feet Ali will travel in 60 seconds, by multiplying 60 second × 300 feet per second, which equals 18,000 feet. Divide 18,000 feet by the length of one lap, or 3,000 feet, and you’ll find that it will take Ali 6 laps to overtake Jeff.

Hence option B is correct!


Answer should be C anyway. since B is 5 laps
User avatar
sandy
Retired Moderator
Joined: 07 Jun 2014
Posts: 4815
Own Kudos [?]: 11277 [0]
Given Kudos: 0
GRE 1: Q167 V156
WE:Business Development (Energy and Utilities)
Send PM
Re: Je? and Ali race each other at the Tentleytown Speedway. [#permalink] New post   30 Dec 2017, 05:57
Expert Reply
I think you are right the answer should be indeed C.
avatar
Emike56
Intern
Intern
Joined: 08 Apr 2018
Posts: 44
Own Kudos [?]: 20 [0]
Given Kudos: 0
Send PM
Re: Je? and Ali race each other at the Tentleytown Speedway. [#permalink] New post   04 Jul 2018, 11:13
sandy wrote:
Explanation

Use the Rate Pie.

Ali is traveling 50 feet per second faster than Jeff is traveling. Therefore, that is the rate at which she is effectively gaining ground on him. Put that in the
lower-right segment of the Rate Pie. We want to know how long it will take her to gain 3,000 feet on him.

Put 3,000 in the top section of the Rate Pie. Now you can see that dividing \(\frac{3000}{50}\) will fill in the last segment of the Rate Pie, telling you how long it takes Ali to do so is 60 seconds. Be aware that choice (E) is an incorrect partial answer.

Now you need to find out how many feet Ali will travel in 60 seconds, by multiplying 60 second × 300 feet per second, which equals 18,000 feet. Divide 18,000 feet by the length of one lap, or 3,000 feet, and you’ll find that it will take Ali 6 laps to overtake Jeff.

Hence option C is correct!

what is the rate pie?
User avatar
D
Carcass
Verbal Expert
Joined: 18 Apr 2015
Posts: 30524
Own Kudos [?]: 36890 [3]
Given Kudos: 26114
Send PM
Re: Je? and Ali race each other at the Tentleytown Speedway. [#permalink] New post   04 Jul 2018, 11:17
2
Expert Reply
1
Bookmarks
Relative speed of Ali with respect to Jeff is 50 feet/second.
Since the track is 3000 ft long, it takes Ali around (3000/50 = 60) seconds to overtake Jeff.
In 60 seconds, Ali will travel 300*60 = 18000 feet.

18000 feet will translate to 6 LAPS since one lap is around 3000 ft long

Therefore, Ali takes 6 laps to overtake Jeff(Option C)
User avatar
D
KarunMendiratta
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Own Kudos [?]: 3273 [1]
Given Kudos: 172
Location: India
WE:Education (Education)
Send PM
Re: Je? and Ali race each other at the Tentleytown Speedway. [#permalink] New post   15 Mar 2021, 23:39
1
sandy wrote:
Jeff and Ali race each other at the Tentleytown Speedway. Ali’s car travels at 300 feet per second, and Je?’s car travels at 250 feet per second. If one lap around the track is 3000 feet long, and each car travels at a constant rate, how many laps will it take Ali to overtake Jeff?

A. 1
B. 5
C. 6
D. 10
E. 60


sandy

Just a question here!

Since, Ali is travelling at a faster rate than Jeff
In 1 second Ali is already 50 feet ahead of Jeff

Don't you think it should be other way around?
User avatar
P
GreenlightTestPrep
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Own Kudos [?]: 12239 [0]
Given Kudos: 136
Send PM

Top Member of the Month
Re: Je? and Ali race each other at the Tentleytown Speedway. [#permalink] New post   23 Mar 2022, 12:19
sandy wrote:
Jeff and Ali race each other at the Tentleytown Speedway. Ali’s car travels at 300 feet per second, and Je?’s car travels at 250 feet per second. If one lap around the track is 3000 feet long, and each car travels at a constant rate, how many laps will it take Ali to overtake Jeff?

A. 1
B. 5
C. 6
D. 10
E. 60

Drill 4
Question: 2
Page: 531

Since the question asks for a certain number of LAPS, let's first rewrite the given information in terms of laps.
300/3000 = 1/10, which means 300 ft = 1/10 laps. So, Ali’s speed of 300 feet per second is equal to a speed of 1/10 laps per second
250/3000 = 1/12, which means 250 ft = 1/12 laps. So, Jeff’s speed of 250 feet per second is equal to a speed of 1/12 laps per second

Since each person travels for the same amount of time, we can start with the following word equation: Ali's travel time (in seconds) = Jeff's travel time (in seconds)
When Ali laps Jeff, Ali has completed 1 lap more than Jeff has.
Let x = the number of laps Ali completes (i.e., Ali's travel distance)
So, x - 1 = the number of laps Jeff completes (i.e., Jeff's travel distance)

time= distance/rate
Plug our values into our word equation to get: (x)/(1/10) = (x - 1)/(1/12)
Simplify: (10)(x) = (12/1)(x - 1)
Simplify: 10x = 12x - 12
Solve: x = 6

Answer: C
User avatar
bumpbot
GRE Prep Club Legend
GRE Prep Club Legend
Joined: 07 Jan 2021
Posts: 5092
Own Kudos [?]: 76 [0]
Given Kudos: 0
Send PM
Re: Je? and Ali race each other at the Tentleytown Speedway. [#permalink] New post   11 Dec 2023, 15:35
Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Prep Club for GRE Bot
gmatclubot
Re: Je? and Ali race each other at the Tentleytown Speedway. [#permalink]
11 Dec 2023, 15:35
Moderators:
adewale223
GRE Instructor
88 posts
bronaugust
GRE Forum Moderator
37 posts
BrushMyQuant
Moderator
1116 posts
VibhuAnurag
GRE Instructor
234 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Main navigation

Partners

GRE Resources

www.ets.org/gre | About | Terms and Conditions and Privacy Policy | Prep Club for GRE Rules | Contact