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f(x) = 2x – 3 f(m) = –11

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sandy
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f(x) = 2x – 3 f(m) = –11 [#permalink] New post   30 Jul 2018, 10:25
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\(f(x) = 2x - 3\)
\(f(m) = -11\)

Quantity A
Quantity B
m
\(\frac{1}{2} f(m)\)


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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A
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sandy
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Re: f(x) = 2x – 3 f(m) = –11 [#permalink] New post   11 Aug 2018, 16:40
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Explanation

The problem gives a function, \(f(x) = 2x – 3\), and then indicates that, when m is plugged in to the function, the answer is –11. Therefore:

\(2m - 3 = -11\)

\(2m = -8\)

\(m = -4\)

Quantity A is equal to –4. The problem indicates that f(m) = –11, so Quantity B is equal to = –5.5. Quantity A is greater.
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f(x) = 2x – 3 f(m) = –11 [#permalink] New post   10 Sep 2021, 08:31
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sandy wrote:
\(f(x) = 2x - 3\)
\(f(m) = -11\)

Quantity A
Quantity B
m
\(\frac{1}{2} f(m)\)


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.


If \(f(m) = -11\), then we are saying that: \(f(m) = 2m - 3 = -11\)

So, now we can solve the following equation \(m\): \(2m - 3 = -11\)

Add \(3\) to both sides: \(2m = -8\)

Divide both sides by \(2\): \(m = -4\)

So, we have:

QUANTITY A: \(-4\)

QUANTITY B: \(\frac{1}{2} f(m) = (\frac{1}{2})(-11) = -5.5\)

Answer: A
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f(x) = 2x – 3 f(m) = –11 [#permalink] New post   11 Dec 2021, 09:48
Given that \(f(x) = 2x - 3\) and \(f(m) = -11\)

Quantity A = m

Let's find out the value of m
To find f(m) we need to replace x with m in f(x)
=> f(m) = 2m - 3 = -11 (given)
=> 2m = -11 + 3 = -8
=> m = -4

Quantity B = \(\frac{1}{2} f(m)\)
= \(\frac{1}{2}\) * -11 = \(\frac{-11}{2}\) = -5.5

Clearly, Quantity A (-4) > Quantity B(-5.5)

So, Answer will be A
Hope it helps!

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f(x) = 2x 3 f(m) = 11 [#permalink] New post   31 Dec 2023, 22:09
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To compare the two quantities we need the value of m.

We know that \(f(m) = -11\)

We also know that \(f(x) = 2x-3\)

Combining both we get,

\(f(m) = 2m-3 = -11\)

\(2m-3 = -11\)

\(2m = -11+3\)

\(2m = -8\)

\(m = -8/2\)

\(m = 4\)

Quantity A = 4

Quantity B is \(1/2*f(m)\).

We know that \(f(m) = -11\)

Quantity B = \(-11/2 = -5.5\)

Quantity B = -5.5

Thus Quantity A is greatest.
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