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A certain automotive dealer sells only cars and trucks, and
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17 Aug 2018, 17:04
17 Aug 2018, 17:04
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A certain automotive dealer sells only cars and trucks, and the ratio of cars to trucks on the lot is 1 to 3. If there are currently 51 trucks for sale, how many cars does the dealer have for sale?
(A) 17
(B) 34
(C) 68
(D) 153
(E) 204
(A) 17
(B) 34
(C) 68
(D) 153
(E) 204
Re: A certain automotive dealer sells only cars and trucks, and
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11 Apr 2020, 20:11
11 Apr 2020, 20:11
sandy wrote:
A certain automotive dealer sells only cars and trucks, and the ratio of cars to trucks on the lot is 1 to 3. If there are currently 51 trucks for sale, how many cars does the dealer have for sale?
(A) 17
(B) 34
(C) 68
(D) 153
(E) 204
(A) 17
(B) 34
(C) 68
(D) 153
(E) 204
Since,there are 51 trucks available
and the automotive dealer sells only cars and trucks, and the ratio of cars to trucks on the lot is 1 : 3
no. of cars available = 17 ( 1: 3 or 17 : 51 and so on....)
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Re: A certain automotive dealer sells only cars and trucks, and
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13 Sep 2021, 07:15
13 Sep 2021, 07:15
1
sandy wrote:
A certain automotive dealer sells only cars and trucks, and the ratio of cars to trucks on the lot is 1 to 3. If there are currently 51 trucks for sale, how many cars does the dealer have for sale?
(A) 17
(B) 34
(C) 68
(D) 153
(E) 204
(A) 17
(B) 34
(C) 68
(D) 153
(E) 204
We can solve this question using equivalent ratios
We'll set up the ratios in the form: # of cars/# of trucks
Let x = the number of cars the dealer has for sale
So we can write: x/51 = 1/3
Cross multiply: (3)(x) = (51)(1)
Simplify: 3x = 51
Solve: x = 51/3 = 17
Answer: A
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