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Re: Every week, Renee is paid $40 per hour for the first 40 hour [#permalink]
can the answer be D?
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Re: Every week, Renee is paid $40 per hour for the first 40 hour [#permalink]
Hovsep wrote:
can the answer be D?

How please explain.
I think, may be not.
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Re: Every week, Renee is paid $40 per hour for the first 40 hour [#permalink]
ruposh6240 wrote:
So, 1600+80(t−40)t=601600+80(t−40)t=60


I don't get it.
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Re: Every week, Renee is paid $40 per hour for the first 40 hour [#permalink]
This is a select one multiple choice question there can be only 1 ans choice. Ans is D
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Re: Every week, Renee is paid $40 per hour for the first 40 hour [#permalink]
amorphous wrote:
This is a select one multiple choice question there can be only 1 ans choice. Ans is D




The one and only answer here is E certainly.
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Re: Every week, Renee is paid $40 per hour for the first 40 hour [#permalink]
ruposh6240 wrote:

Edited:

Let 't' = number of hours Renee will have to work.
Concept: The average rate Renee gets paid is equal to the total wages earned divided by the total number of hours worked.
Rene earns\($40\) per hour for the first \(40\) hours, so she makes\(40 × 40\)= \($1,600\) in the first \(40\) hours. She also earns\($80\) for every hour after 40 hours, for additional pay of\($80(t – 40)\). Therefore, her total pay can be calculated as:

So,\(\frac{1600+80(t−40)}{t}\)=\(60\)
Or, \(1600+80t-3200\)=\(60t\)
Or, \(20t\)=\(1600\)
or, \(t\)=\(80 hours\)

Ans. (E)
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Re: Every week, Renee is paid $40 per hour for the first 40 hour [#permalink]
1
Let, extra hours = x

(40*40 + 80*x) / (40+x) = 60
=> 1600 + 80*x = 2400 + 60*x
=> 20*x = 800
=> x = 40

So, in total = 40 + 40 = 80 (E)
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Re: Every week, Renee is paid $40 per hour for the first 40 hour [#permalink]
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Re: Every week, Renee is paid $40 per hour for the first 40 hour [#permalink]
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