WRONG SOLUTION MY MISTAKE! IGNORE THIS AND SCROLL DOWN




Since it is mentioned that x, y and z are positive you can divide them without flipping the inequality.

Given: $x > yz$

Dividing both sides with y

$\frac{x}{y} > \frac{yz}{y}$ or $\frac{x}{y} > z$... So A is true

Dividing both sides with z

$\frac{x}{z} > \frac{yz}{z}$ or $\frac{x}{z} > y$... So B is true

Dividing both sides with yy

$\frac{x}{yz} > \frac{yz}{yz}$ or $\frac{x}{yz} > 1$... So C is true

Option D cant be true as it is a direct contradiction of the stement given in problem.