Carcass wrote:
If f footballs cost d dollars, then in terms of d and f how many dollars would 10 footballs cost?
A. \(10 f d\)
B.\(f\frac{d}{10}\)
C. \(10\frac{d}{f}\)
D. \(d\frac{f}{10}\)
E. \(f\frac{d}{10}\)
If f footballs cost d dollars...With this info, how much does ONE football cost?
If you're not sure, try testing some values.
For example, if 3 footballs cost 15 dollars, then ONE football costs 5 dollars (aka 15/3 dollars)
If 7 footballs cost 28 dollars, then ONE football costs 4 dollars (aka 28/7 dollars)
If 10 footballs cost 80 dollars, then ONE football costs 8 dollars (aka 80/8 dollars)
See the pattern?
If f footballs cost d dollars, then ONE football costs
d/f dollars
If ONE football costs
d/f dollars, then
TWO football costs
(2)(d/f) dollars
If ONE football costs
d/f dollars, then
THREE football costs
(3)(d/f) dollars
.
.
.
If ONE football costs
d/f dollars, then
TEN football costs
(10)(d/f) dollars
Answer: C
Cheers,
Brent