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Cyclist M leaves point P at 12 noon and travels in a straigh
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19 Sep 2018, 00:40
19 Sep 2018, 00:40
00:00
Question Stats:
85% (01:29) correct
14% (02:13) wrong based on 21 sessions
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Cyclist M leaves point P at 12 noon and travels in a straight path at a constant velocity of 20 miles per hour. Cyclist N leaves point P at 2 PM, travels the same path at a constant velocity, and overtakes M at 4 PM. What was the average speed of N?
(A) 15
(B) 24
(C) 30
(D) 35
(E) 40
(A) 15
(B) 24
(C) 30
(D) 35
(E) 40
Re: Cyclist M leaves point P at 12 noon and travels in a straigh
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19 Sep 2018, 02:51
19 Sep 2018, 02:51
3
There are two cyclists traveling along the same path.
One of them lets say cyclist A has a speed of 20 miles per hr and starts traveling at 12 PM
Another cyclist let us say B has a speed that we do not know and that is what is required by the question.
Cyclist B starts traveling along the same path as A but 2 hrs later than A i.e. at 2PM
Also at 4PM both cyclists travel the same distance from the starting point P.
Let us find out how much can cyclist A travel in 4 hrs, that would be \(20*4 = 80\) miles
Since cyclist B started at 2PM and reached the exact distance as cyclist A at 4PM. Cyclist B traveled for 2 hrs only.
Therefore if Cyclist B speed was x miles per hr then 2x = 80
or, \(x = 40\) which is the speed of cyclist B
One of them lets say cyclist A has a speed of 20 miles per hr and starts traveling at 12 PM
Another cyclist let us say B has a speed that we do not know and that is what is required by the question.
Cyclist B starts traveling along the same path as A but 2 hrs later than A i.e. at 2PM
Also at 4PM both cyclists travel the same distance from the starting point P.
Let us find out how much can cyclist A travel in 4 hrs, that would be \(20*4 = 80\) miles
Since cyclist B started at 2PM and reached the exact distance as cyclist A at 4PM. Cyclist B traveled for 2 hrs only.
Therefore if Cyclist B speed was x miles per hr then 2x = 80
or, \(x = 40\) which is the speed of cyclist B
Re: Cyclist M leaves point P at 12 noon and travels in a straigh
[#permalink]
19 Sep 2018, 09:03
19 Sep 2018, 09:03
amorphous wrote:
There are two cyclists traveling along the same path.
One of them lets say cyclist A has a speed of 20 miles per hr and starts traveling at 12 PM
Another cyclist let us say B has a speed that we do not know and that is what is required by the question.
Cyclist B starts traveling along the same path as A but 2 hrs later than A i.e. at 2PM
Also at 4PM both cyclists travel the same distance from the starting point P.
Let us find out how much can cyclist A travel in 4 hrs, that would be \(20*4 = 80\) miles
Since cyclist B started at 2PM and reached the exact distance as cyclist A at 4PM. Cyclist B traveled for 2 hrs only.
Therefore if Cyclist B speed was x miles per hr then 2x = 80
or, \(x = 40\) which is the speed of cyclist B
One of them lets say cyclist A has a speed of 20 miles per hr and starts traveling at 12 PM
Another cyclist let us say B has a speed that we do not know and that is what is required by the question.
Cyclist B starts traveling along the same path as A but 2 hrs later than A i.e. at 2PM
Also at 4PM both cyclists travel the same distance from the starting point P.
Let us find out how much can cyclist A travel in 4 hrs, that would be \(20*4 = 80\) miles
Since cyclist B started at 2PM and reached the exact distance as cyclist A at 4PM. Cyclist B traveled for 2 hrs only.
Therefore if Cyclist B speed was x miles per hr then 2x = 80
or, \(x = 40\) which is the speed of cyclist B
Thank you very much! Can you provide some materials on this very topic or reference me to some for more practice? I am weak in work/rate problems.
