sandy wrote:
An isosceles right triangle has an area of 50. What is the length of the hypotenuse?
(A) \(5\)
(B) \(5\sqrt{2}\)
(C) \(5\sqrt{3}\)
(D) \(10\)
(E) \(10\sqrt{2}\)
Here's an isosceles right triangle with sides of length x
Area of triangle = (base)(height)/2 So, we can write: 50 = (x)(x)/2
In other words: 50 = x²/2
We get: 100 = x²
Solve: x = 10
So, our triangle looks like this:
![Image](https://i.imgur.com/rrrB62O.png)
To find the length of the hypotenuse (k), we can apply the Pythagorean Theorem:
We get: 10² + 10² = k²
Keep going: 200 = k²
So, k = √200
= √[(100)(2)]
= (√100)(√2)
= 10√2
Answer: E
Cheers,
Brent