Carcass wrote:
Attachment:
rectangle.jpg
In the figure, ABCD is a rectangle and E is a point on the side AB. If AB = 10 and AD = 5, what is the area of the shaded region in the figure?
(A) 25
(B) 30
(C) 35
(D) 40
(E) 45
Area of rectangle = (base)(height)So, area of rectangle ABCD = (10)(5) =
50Now let's calculate the area of the UNSHADED triangle DEC
Why?
Once we know the area of the UNSHADED portion, we can subtract it from
50 to get the area of the SHADED portion.
Area of triangle = (base)(height)/2So, area of ∆DEC = (10)(5)/2 =
25 Area of SHADED portion = (Area of rectangle) - (Area of UNSHADED portion)
So, area of SHADED portion =
50 -
25 = 25
Answer: A
Cheers,
Brent