sandy wrote:
A burger eating contest had 25 contestants and 450 burgers were consumed. The bottom \(\frac{3}{5}\) of the contestants ate at least 15 burgers each but not more than 20. And the next 9 contestants ate at least 20 burgers each. What is the maximum number of burgers that the winner has consumed to win the contest.
GIVEN: 450 burgers were consumed
To MAXIMIZE the number of burgers the winner ate, we must MINIMIZE the number of burgers everyone else ate.
The bottom 3/5 of the contestants ate at least 15 burgers each but not more than 20. 3/5 of 25 = 15
Since we're MINIMIZING the number of burgers everyone else ate, we'll say that all 15 people ate 15 burgers EACH
(15)(15) =
225, so these 15 people consumed a total of
225 burgers
The next 9 contestants ate at least 20 burgers each Since we're MINIMIZING the number of burgers everyone else ate, we'll say that all 9 people ate 20 burgers EACH
(9)(20) =
180, so these 9 people consumed a total of
180 burgers
What is the maximum number of burgers that the winner has consumed to win the contest.Number of burgers consumed by everyone other than the winner =
225 +
180 =
405 burgers
So, the winner must have each the remaining burgers.
450 -
405 = 45
Answer: 45
Cheers,
Brent