GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
In the figure, ABCD is a square, and OB is a radius of the c
[#permalink]
15 Oct 2018, 03:28
15 Oct 2018, 03:28
Expert Reply
00:00
Question Stats:
100% (00:46) correct
0% (00:00) wrong based on 18 sessions
Hide Show timer Statistics
Attachment:
#GREpracticequestion ABCD is a square, and OB is a radius of the circle.jpg [ 21.14 KiB | Viewed 3577 times ]
In the figure, ABCD is a square, and OB is a radius of the circle. If BC is a tangent to the circle and PC = 2, then what is the area of the square?
(A) 16
(B) 20
(C) 25
(D) 36
(E) 42
Re: In the figure, ABCD is a square, and OB is a radius of the c
[#permalink]
17 Oct 2018, 22:21
17 Oct 2018, 22:21
1
Expert Reply
Carcass wrote:
Attachment:
The attachment figure.jpg is no longer available
In the figure, ABCD is a square, and OB is a radius of the circle. If BC is a tangent to the circle and PC = 2, then what is the area of the square?
(A) 16
(B) 20
(C) 25
(D) 36
(E) 42
BC is tangent to radius OB, so angle OBC is 90°
CO=PC+PO=2+3=5
Now in ∆OBC, a right angled triangle
\(OB^2+BC^2=CO^2.....BC^2=5^2-3^2=4^2....BC=4\)
So side of square is 4..
Area is 4*4=16
A
Attachments
PicsArt_10-18-10.41.40.jpg [ 13.07 KiB | Viewed 4539 times ]
gmatclubot
Re: In the figure, ABCD is a square, and OB is a radius of the c [#permalink]
17 Oct 2018, 22:21
Moderators:
