sandy wrote:
The integer m is a multiple of 154, 250, and 264. Which of the following do NOT have to be
factors of m?
Indicate all possible valuesA. 176
B. 242
C. 275
D. 924
E. 2,500
F. 7,000
Drill 3
Question: 12
Page: 290
A very straight forward answer.
if m is a multiple of 154, 250, & 256, it means that m is divisible by 154, 250, 264. So;
\(m/154\), \(m/ 250\), \(m/264\) will yield a remainder of zero.
This means that all the prime factors of each of the denominators are in the numerator m. Prime factors of 154 = 2 * 7 * 11
Prime factors of 250 = 2 * 5 * 5 * 5
Prime factors of 264 = 2 * 2 * 2 * 3 * 11
So, m at least have the following prime factors.
Three 2s, one 3, three 5s, one 7, and one 11.
Now check each option.
Option A: prime factors of 176 -> 2,2,2,2,11 ----> We do not have four 2s in m. Therefore 176 can't be a factor of m.
Correct Option B: prime factors of 242 -> 2,11,11 ----> Not a factor.
CorrectOption C: prime factors of 275 -> 5,5,11 ---> Factor.
IncorrectOption D: prime factors of 924 -> 2,2,3,7,11 ---> Factor.
IncorrectOption E: prime factors of 2500 -> 2,2,5,5,5,5 ---> Not Factor. m doesn't have four 5s.
CorrectOption F: prime factors of 7000 -> 2,2,2,5,5,5,7 ---> Factor.
Incorrect