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x>0
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21 Oct 2018, 08:22
21 Oct 2018, 08:22
Expert Reply
00:00
Question Stats:
89% (00:39) correct
10% (00:40) wrong based on 64 sessions
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\(x > 0\)
Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(\frac{x+1}{x}\) |
\(\frac{x}{x+1}\) |
Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
Re: x>0
[#permalink]
21 Oct 2018, 19:40
21 Oct 2018, 19:40
Carcass wrote:
\(x > 0\)
Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(\frac{x+1}{x}\) |
\(\frac{x}{x+1}\) |
Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
\(\frac{x+1}{x} = 1 + \frac{1}{x}\),
This equation must be greater than 1 always
where as,
\(\frac{x}{x+1}\) must be less than 1, because the denominator is greater compared to QTY A
therefore QTY A > QTY B
