GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
x>0
[#permalink]
21 Oct 2018, 08:22
21 Oct 2018, 08:22
Expert Reply
00:00
Question Stats:
88% (00:40) correct
11% (00:44) wrong based on 68 sessions
Hide Show timer Statistics
\(x > 0\)
Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(\frac{x+1}{x}\) |
\(\frac{x}{x+1}\) |
Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
Re: x>0
[#permalink]
21 Oct 2018, 19:40
21 Oct 2018, 19:40
Carcass wrote:
\(x > 0\)
Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(\frac{x+1}{x}\) |
\(\frac{x}{x+1}\) |
Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
\(\frac{x+1}{x} = 1 + \frac{1}{x}\),
This equation must be greater than 1 always
where as,
\(\frac{x}{x+1}\) must be less than 1, because the denominator is greater compared to QTY A
therefore QTY A > QTY B
