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A, B, and C are three unequal faces of a rectangular tank. T
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15 Oct 2018, 03:36
15 Oct 2018, 03:36
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Question Stats:
77% (03:09) correct
22% (01:43) wrong based on 53 sessions
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A, B, and C are three unequal faces of a rectangular tank. The tank contains a certain amount of water. When the tank is based on the face A, the height of the water is half the height of the tank. The dimensions of the side B are 3 ft × 4 ft and the dimensions of side C are 4 ft × 5 ft. What is the measure of the height of the water in the tank in feet?
(A) 2
(B) 2.5
(C) 3
(D) 4
(E) 5
(A) 2
(B) 2.5
(C) 3
(D) 4
(E) 5
Re: A, B, and C are three unequal faces of a rectangular tank. T
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17 Oct 2018, 20:53
17 Oct 2018, 20:53
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Expert Reply
Carcass wrote:
A, B, and C are three unequal faces of a rectangular tank. The tank contains a certain amount of water. When the tank is based on the face A, the height of the water is half the height of the tank. The dimensions of the side B are 3 ft × 4 ft and the dimensions of side C are 4 ft × 5 ft. What is the measure of the height of the water in the tank in feet?
(A) 2
(B) 2.5
(C) 3
(D) 4
(E) 5
(A) 2
(B) 2.5
(C) 3
(D) 4
(E) 5
I. Dimensions of A
The face B is 3*4 and face C is 4*5...
So face A is 3*5
II. where does face A lie
Quote:
Tank is based on face A
So A is the base of tank
III. what does above info mean
Base has sides 3*5 so the third side 4 is the height
height of the water is half the height of tank, so \(\frac{4}{2}=2\)
A
Re: A, B, and C are three unequal faces of a rectangular tank. T
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03 Nov 2018, 13:09
03 Nov 2018, 13:09
1
Make diagram to understand better
