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|a| > |d|
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27 Nov 2018, 15:47
27 Nov 2018, 15:47
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Question Stats:
48% (01:50) correct
51% (01:30) wrong based on 402 sessions
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\(|a| > |d|\)
\(|a| * b^3 * c^2 * |d| * e^5 * f^6 * g < 0\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
\(|a| * b^3 * c^2 * |d| * e^5 * f^6 * g < 0\)
Quantity A |
Quantity B |
\(g( |a| * b * e)\) |
\(g(b * e * |d|\)) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Re: |a| > |d|
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28 Nov 2018, 12:08
28 Nov 2018, 12:08
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I think you didn't evaluate carefully the question Sir.
\(|a| > |d|\) means that a is > 0 and further from zero on the number line than |d| which is still positive and close to zero.
We also do know that \(|a|, c^2, |d|,\) and \(f^6\) must be positive > 0
On the other hand, \(b^3, e^5\), and \(g\) must be a negative number <0 , of which all 3 numbers are negative OR two are positive and one is negative to obtain \(beg < 0\)
Looking at the two quantities, we do have
A) \(|a| * beg\)
B) \(|d| * beg\)
and we do know for sure that beg <0 or negative regardless the sign of the numbers.
A negative number * a bigger positive number (\(|a|\)) we will have a number further from zero on the negative side of the number line.
A negative number * a smaller positive number ( \(|d|\) ) we will have a number closer to zero on the negative side of the number line.
Therefore, \(|d| > |a|\) and the answer is B
\(|a| > |d|\) means that a is > 0 and further from zero on the number line than |d| which is still positive and close to zero.
We also do know that \(|a|, c^2, |d|,\) and \(f^6\) must be positive > 0
On the other hand, \(b^3, e^5\), and \(g\) must be a negative number <0 , of which all 3 numbers are negative OR two are positive and one is negative to obtain \(beg < 0\)
Looking at the two quantities, we do have
A) \(|a| * beg\)
B) \(|d| * beg\)
and we do know for sure that beg <0 or negative regardless the sign of the numbers.
A negative number * a bigger positive number (\(|a|\)) we will have a number further from zero on the negative side of the number line.
A negative number * a smaller positive number ( \(|d|\) ) we will have a number closer to zero on the negative side of the number line.
Therefore, \(|d| > |a|\) and the answer is B
Re: |a| > |d|
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28 Nov 2018, 12:39
28 Nov 2018, 12:39
6
Answer: B
|a | > |d|
A: g(|a| * b * e)
B. g(b * e * |d|)
|a|*b^3 * c^2 * |d| * e^5 * f^6 * g <0
We analyze the above expression,
|a|, c^2, |d|, f^6 are definitely positive,
Odd numbers(1 or 3) of other factors(b^3, e^5, g) are negative. Then either one of (b, e, g) are negative or the three of them
A: g(|a| * b * e)
As explained in above, either the three of (b, e, g) are negative or one of them
1: three of them are negative then we will have :
g(|a| * b * e) = g(positive * negative * negative) = g(positive) = negative (because g is considered as negative)
2.one of them is negative ( for example e):
g(|a| * b * e) = g(positive * positive * negative) = g(negative) = negative (because g is considered as positive here)
[the same situation happens when g or b is negative)
B. g(b * e * |d|)
As explained in above, either the three of (b, e, g) are negative or one of them
1: three of them are negative then we will have :
g(|d| * b * e) = g(positive * negative * negative) = g(positive) = negative (because g is considered as negative)
2.one of them is negative ( for example e):
g(|d| * b * e) = g(positive * positive * negative) = g(negative) = negative (because g is considered as positive here)
[the same situation happens when g or b is negative)
So we see both of them are negative, the one which is less is bigger, as |a| > |d| then B is bigger than A.
|a | > |d|
A: g(|a| * b * e)
B. g(b * e * |d|)
|a|*b^3 * c^2 * |d| * e^5 * f^6 * g <0
We analyze the above expression,
|a|, c^2, |d|, f^6 are definitely positive,
Odd numbers(1 or 3) of other factors(b^3, e^5, g) are negative. Then either one of (b, e, g) are negative or the three of them
A: g(|a| * b * e)
As explained in above, either the three of (b, e, g) are negative or one of them
1: three of them are negative then we will have :
g(|a| * b * e) = g(positive * negative * negative) = g(positive) = negative (because g is considered as negative)
2.one of them is negative ( for example e):
g(|a| * b * e) = g(positive * positive * negative) = g(negative) = negative (because g is considered as positive here)
[the same situation happens when g or b is negative)
B. g(b * e * |d|)
As explained in above, either the three of (b, e, g) are negative or one of them
1: three of them are negative then we will have :
g(|d| * b * e) = g(positive * negative * negative) = g(positive) = negative (because g is considered as negative)
2.one of them is negative ( for example e):
g(|d| * b * e) = g(positive * positive * negative) = g(negative) = negative (because g is considered as positive here)
[the same situation happens when g or b is negative)
So we see both of them are negative, the one which is less is bigger, as |a| > |d| then B is bigger than A.
