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In this diagram, the circle is inscribed in the square.
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30 Nov 2018, 17:17
30 Nov 2018, 17:17
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In this diagram, the circle is inscribed in the square.
GRE exam - In this diagram, the circle is inscribed in the square. .jpg [ 8.91 KiB | Viewed 11512 times ]
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Attachment:
GRE exam - In this diagram, the circle is inscribed in the square. .jpg [ 8.91 KiB | Viewed 11512 times ]
Quantity A |
Quantity B |
Length of diagonal AC |
\(\frac{5r}{2}\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Re: In this diagram, the circle is inscribed in the square.
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01 Dec 2018, 10:29
01 Dec 2018, 10:29
2
2r = diameter of the circle.
Diameter of the circle = side of the square
since the adjacent sides of the squares are at 90 degrees, the diagonal = \(2r\sqrt{2}\)
This is because a 90-45-45 triangle will be formed between 2 sides of the square and the diagonal
now simplify
option A is:
\(2r\sqrt{2}\)
option B is:
\(\frac{5r}{2}\)
cancel r from both sides, then multiplying both sides by 2 we get,
option A = \(4\sqrt{2}\)
option B = 5
Diameter of the circle = side of the square
since the adjacent sides of the squares are at 90 degrees, the diagonal = \(2r\sqrt{2}\)
This is because a 90-45-45 triangle will be formed between 2 sides of the square and the diagonal
now simplify
option A is:
\(2r\sqrt{2}\)
option B is:
\(\frac{5r}{2}\)
cancel r from both sides, then multiplying both sides by 2 we get,
option A = \(4\sqrt{2}\)
option B = 5
Re: In this diagram, the circle is inscribed in the square.
[#permalink]
11 Jan 2019, 17:15
11 Jan 2019, 17:15
1
amorphous wrote:
2r = diameter of the circle.
Diameter of the circle = side of the square
since the adjacent sides of the squares are at 90 degrees, the diagonal = \(2r\sqrt{2}\)
This is because a 90-45-45 triangle will be formed between 2 sides of the square and the diagonal
now simplify
option A is:
\(2r\sqrt{2}\)
option B is:
\(\frac{5r}{2}\)
cancel r from both sides, then multiplying both sides by 2 we get,
option A = \(4\sqrt{2}\)
option B = 5
Diameter of the circle = side of the square
since the adjacent sides of the squares are at 90 degrees, the diagonal = \(2r\sqrt{2}\)
This is because a 90-45-45 triangle will be formed between 2 sides of the square and the diagonal
now simplify
option A is:
\(2r\sqrt{2}\)
option B is:
\(\frac{5r}{2}\)
cancel r from both sides, then multiplying both sides by 2 we get,
option A = \(4\sqrt{2}\)
option B = 5
If it does not mention in the question how do we deduce that r is the radius or side or diagonal.
