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1/x + 1/x
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20 Oct 2018, 06:48
20 Oct 2018, 06:48
Expert Reply
00:00
Question Stats:
79% (00:35) correct
20% (00:25) wrong based on 110 sessions
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\(x \neq 0\)
Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(\frac{1}{x} + \frac{1}{x}\) |
\(\frac{1}{x}*\frac{1}{x}\) |
Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
Re: 1/x + 1/x
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20 Oct 2018, 20:08
20 Oct 2018, 20:08
2
Carcass wrote:
\(x \neq 0\)
Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(\frac{1}{x} + \frac{1}{x}\) |
\(\frac{1}{x}*\frac{1}{x}\) |
Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
Value of x\neq 0, so x can be any value except 0
Qty A = \(\frac{1}{x} + \frac{1}{x}= \frac{1}{x}\)
Qty B = \(\frac{1}{x}*\frac{1}{x} = \frac{1}{x^2}\)
If x= 1, then QTY A = QTY B
If x= 2 then QTY A > QTY B
Hence the option is D
