Carcass wrote:
Square and an equilateral triangle each have sides of length 5. What is the ratio of the area of the square to the area of the triangle?
A. \(\frac{4}{3}\)
B. \(\frac{16}{9}\)
C. \(\frac{3}{4}\)
D. \(\frac{4\sqrt{3}}{3}\)
E. \(\frac{16\sqrt{3}}{9}\)
Area of square = \(a^2\)
Area of equilateral triangle =\(a^2\frac{\sqrt{3}}{4}\)
ratio of the area of the square to the area of the triangle = \(a^2\):\(a^2\frac{\sqrt{3}}{4}\)=1:\(\frac{\sqrt{3}}{4}\)=\(\frac{4}{\sqrt{3}}\)=\(\frac{4\sqrt{3}}{3}\)
So, irrespective of the dimension of side, the ratio will remain the same.