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O is the circle’s center and ∠POR is a right angle.
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30 Jan 2019, 08:08
30 Jan 2019, 08:08
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Question Stats:
58% (01:29) correct
41% (01:02) wrong based on 99 sessions
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O is the circle’s center and ∠POR is a right angle.
Quantity A |
Quantity B |
OR |
QR |
Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
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O is the circle’s center and ∠POR is a right angle.
[#permalink]
30 Jan 2019, 09:11
30 Jan 2019, 09:11
1
amorphous wrote:
Attachment:
circle dotted.png
O is the circle’s center and ∠POR is a right angle.
Quantity A |
Quantity B |
OR |
QR |
Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
Useful property: In a triangle, the side OPPOSITE a larger angle is longer than the side OPPOSITE the smaller angle
Opposite angles are equal, so ∠POQ is also 43°
Since we're told ∠POR = 90°, we can conclude that ∠QOR = 47°
Since angles in a triangle add to 180°, we can conclude that ∠OQR = 43°
∠QOR is greater than ∠OQR
So, the side OPPOSITE ∠QOR (QR) must be greater than the side OPPOSITE ∠OQR (OR)
In other words, QR > OR
Answer: B
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Re: O is the circle’s center and ∠POR is a right angle.
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03 Feb 2019, 20:27
03 Feb 2019, 20:27
The answer is wrong but the concept is correct
Opposite angles are equal so <POQ = 43
<QOR = 90 - 43 = 47
Also <OQR = 180 - (90+47) = 43
Hence, from the scenario opposite side of the greater angle has greatest length
QR > OR
The answer is B
Opposite angles are equal so <POQ = 43
<QOR = 90 - 43 = 47
Also <OQR = 180 - (90+47) = 43
Hence, from the scenario opposite side of the greater angle has greatest length
QR > OR
The answer is B
