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For the integers a,b
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15 Dec 2015, 20:30
15 Dec 2015, 20:30
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Question Stats:
20% (00:37) correct
80% (01:10) wrong based on 5 sessions
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For the integers a,b and c the sum of a and b is 75% of c.
A : (3/4) (a+b)
B: (4/3) (c)
I solved it as A: 3/4 x 75/100 x C = 9/16 C
B : 4/3 C
Removing the value of C, B will be greater. Since we do not value of C, it is D.
Is my method is right?Discuss.
Thank You.
A : (3/4) (a+b)
B: (4/3) (c)
I solved it as A: 3/4 x 75/100 x C = 9/16 C
B : 4/3 C
Removing the value of C, B will be greater. Since we do not value of C, it is D.
Is my method is right?Discuss.
Thank You.
Re: For the integers a,b
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26 Feb 2016, 09:56
26 Feb 2016, 09:56
5
The expert post above is incorrect, and I think they misread the op's question. yes the op's approach is correct.
Because we do not know the value of 'c', we cannot determine, so the correct answer is D.
If c>0, then Quantity B will be larger.
If c=0, then the Quantities are equal.
If c<0, then Quantity A will be larger.
The trap here is it only says integers. So we must test for 0 and negatives as well as positives.
Because we do not know the value of 'c', we cannot determine, so the correct answer is D.
If c>0, then Quantity B will be larger.
If c=0, then the Quantities are equal.
If c<0, then Quantity A will be larger.
The trap here is it only says integers. So we must test for 0 and negatives as well as positives.
General Discussion
Re: For the integers a,b
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16 Dec 2015, 02:49
16 Dec 2015, 02:49
Expert Reply
victory wrote:
For the integers a,b and c the sum of a and b is 75% of c.
A : (3/4) (a+b)
B: (4/3) (c)
I solved it as A: 3/4 x 75/100 x C = 9/16 C
B : 4/3 C
Removing the value of C, B will be greater. Since we do not value of C, it is D.
Is my method is right?Discuss.
Thank You.
A : (3/4) (a+b)
B: (4/3) (c)
I solved it as A: 3/4 x 75/100 x C = 9/16 C
B : 4/3 C
Removing the value of C, B will be greater. Since we do not value of C, it is D.
Is my method is right?Discuss.
Thank You.
I think your method is correct! B is indeed greater.
