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In right triangle ABC above, side AB has a length of x units
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21 Oct 2018, 08:38
21 Oct 2018, 08:38
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Question Stats:
94% (01:06) correct
5% (02:11) wrong based on 39 sessions
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In right triangle ABC above, side AB has a length of x units, side AC has a length of 12 units, and side BC has a length of x + 8 units. What is the area of ABC in square units?
Show: :: square units
30
Re: In right triangle ABC above, side AB has a length of x units
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21 Oct 2018, 19:33
21 Oct 2018, 19:33
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Carcass wrote:
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triangle.jpg
In right triangle ABC above, side AB has a length of x units, side AC has a length of 12 units, and side BC has a length of x + 8 units. What is the area of ABC in square units?
Show: :: square units
30
To find the area of the right-angled triangle, the height "x" is required.
As per the information,
\(12^2 + x^2 = (x + 8)^2\)
or \(144 + x^2 = x^2 + 16x + 64\)
or \(x = 5\)
Area of triangle = \(\frac{1}{2} * AC(base) * Height(AB) = \frac{1}{2}* 12 * 5 = 30\)
In right triangle ABC above, side AB has a length of x units
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16 Mar 2019, 00:42
16 Mar 2019, 00:42
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#GREpracticequestion In right triangle ABC above, side AB has a length.jpg [ 11.85 KiB | Viewed 5954 times ]
In right triangle ABC above, side AB has a length of x units, side AC has a length of 12 units, and side BC has a length of x + 8 units. What is the area of ABC in square units?
Show: :: Square Units
30
