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In right triangle ABC above, side AB has a length of x units
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21 Oct 2018, 08:38
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In right triangle ABC above, side AB has a length of x units, side AC has a length of 12 units, and side BC has a length of x + 8 units. What is the area of ABC in square units?
Re: In right triangle ABC above, side AB has a length of x units
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21 Oct 2018, 19:33
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Carcass wrote:
Attachment:
triangle.jpg
In right triangle ABC above, side AB has a length of x units, side AC has a length of 12 units, and side BC has a length of x + 8 units. What is the area of ABC in square units?
In right triangle ABC above, side AB has a length of x units
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16 Mar 2019, 00:42
Expert Reply
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#GREpracticequestion In right triangle ABC above, side AB has a length.jpg [ 11.85 KiB | Viewed 6586 times ]
In right triangle ABC above, side AB has a length of x units, side AC has a length of 12 units, and side BC has a length of x + 8 units. What is the area of ABC in square units?
Re: In right triangle ABC above, side AB has a length of x units
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20 Mar 2019, 16:30
1
Expert Reply
First we have to solve for x. Using the Pythagorean theorem:
x² + 12² = (x + 8)²
Expand the right:
x² + 12² = x² + 16x + 64
Subtract x² from both sides:
12² = 16x + 64
Subtract 64:
12² - 64 = 16x
Simplify:
80 = 16x
Divide by 16:
x = 5
If x = 5, then AB = 5 and AC = 12. If we use AB as the base, then AC is the height, and the area is one half of the base times the height. 5*12 = 60, and one half of that is 30. So the area of the triangle is 30.
Re: In right triangle ABC above, side AB has a length of x units
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01 Apr 2021, 03:38
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