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What is the maximum number of 3x3 squares that can be formed
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25 Mar 2019, 05:07
25 Mar 2019, 05:07
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Question Stats:
42% (01:31) correct
57% (01:02) wrong based on 35 sessions
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#GREpracticequestion What is the maximum number of 3x3 squares.jpg [ 55.31 KiB | Viewed 15514 times ]
What is the maximum number of 3x3 squares that can be formed from the squares in the 6x6 checkerboard to the right?
(A) 4
(B) 6
(C) 12
(D) 16
(E) 24
Re: What is the maximum number of 3x3 squares that can be formed
[#permalink]
23 Nov 2019, 13:22
23 Nov 2019, 13:22
1
Let's consider the picture above.
For each row we can pick exactly 4 different groups of 3 consecutive boxes.
In the same manner, for each column we can select 4 different groups of 3 consecutive boxes.
Therefore, snce we are required the maximum number of 3x3 squares of the chessboard,
we need to combine our combinations:
4 * 4 = 16
Answer is D.
Hope is clear.
For each row we can pick exactly 4 different groups of 3 consecutive boxes.
In the same manner, for each column we can select 4 different groups of 3 consecutive boxes.
Therefore, snce we are required the maximum number of 3x3 squares of the chessboard,
we need to combine our combinations:
4 * 4 = 16
Answer is D.
Hope is clear.
Re: What is the maximum number of 3x3 squares that can be formed
[#permalink]
23 Nov 2019, 13:57
23 Nov 2019, 13:57
sal60 wrote:
Let's consider the picture above.
For each row we can pick exactly 4 different groups of 3 consecutive boxes.
In the same manner, for each column we can select 4 different groups of 3 consecutive boxes.
Therefore, snce we are required the maximum number of 3x3 squares of the chessboard,
we need to combine our combinations:
4 * 4 = 16
Answer is D.
Hope is clear.
For each row we can pick exactly 4 different groups of 3 consecutive boxes.
In the same manner, for each column we can select 4 different groups of 3 consecutive boxes.
Therefore, snce we are required the maximum number of 3x3 squares of the chessboard,
we need to combine our combinations:
4 * 4 = 16
Answer is D.
Hope is clear.
Can you elaborate a little bit. I do not know how you get the 4*4
