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x/15 > y/25

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Carcass
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x/15 > y/25 [#permalink] New post   25 Mar 2019, 11:47
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\(\frac{x}{15} > \frac{y}{25}\)

Quantity A
Quantity B
\(6y+5x\)
\(10x+3y\)


Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
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x/15 > y/25 [#permalink] New post   25 Mar 2019, 14:47
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Carcass wrote:
\(\frac{x}{15} > \frac{y}{25}\)

Quantity A
Quantity B
\(6y+5x\)
\(10x+3y\)


Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.


Given: x/15 > y/25
The LCM of 15 and 25 is 75, so let's multiply both sides by 75 to get: 75x/15 > 75y/25
Simplify: to get: 5x > 3y

Now let's examine the two quantities:
QUANTITY A: 6y + 5x
QUANTITY B: 10x + 3y

Subtract 5x from both quantities:
QUANTITY A: 6y
QUANTITY B: 5x + 3y

Subtract 3y from both quantities:
QUANTITY A: 3y
QUANTITY B: 5x

Since we already know that 5x > 3y, the correct answer is B

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Re: x/15 > y/25 [#permalink] New post   04 Aug 2024, 02:15
Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: x/15 > y/25 [#permalink]
04 Aug 2024, 02:15
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