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x/15 > y/25
[#permalink]
25 Mar 2019, 11:47
25 Mar 2019, 11:47
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Question Stats:
58% (01:15) correct
42% (01:42) wrong based on 100 sessions
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\(\frac{x}{15} > \frac{y}{25}\)
Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(6y+5x\) |
\(10x+3y\) |
Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
x/15 > y/25
[#permalink]
25 Mar 2019, 14:47
25 Mar 2019, 14:47
1
1
Bookmarks
Carcass wrote:
\(\frac{x}{15} > \frac{y}{25}\)
Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(6y+5x\) |
\(10x+3y\) |
Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
Given: x/15 > y/25
The LCM of 15 and 25 is 75, so let's multiply both sides by 75 to get: 75x/15 > 75y/25
Simplify: to get: 5x > 3y
Now let's examine the two quantities:
QUANTITY A: 6y + 5x
QUANTITY B: 10x + 3y
Subtract 5x from both quantities:
QUANTITY A: 6y
QUANTITY B: 5x + 3y
Subtract 3y from both quantities:
QUANTITY A: 3y
QUANTITY B: 5x
Since we already know that 5x > 3y, the correct answer is B
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Re: x/15 > y/25
[#permalink]
22 Jan 2026, 09:39
22 Jan 2026, 09:39
Hello from the GRE Prep Club BumpBot!
Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
