GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
A precious stone was accidentally dropped and broke into 3 p
[#permalink]
14 Apr 2019, 10:13
14 Apr 2019, 10:13
Expert Reply
1
Bookmarks
00:00
Question Stats:
71% (00:54) correct
28% (00:47) wrong based on 69 sessions
Hide Show timer Statistics
A precious stone was accidentally dropped and broke into 3 pieces of equal weight. The value of this type of stone is always proportional to the square of its weight.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The value of the 3 broken pieces together |
The value of the original stone |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Re: A precious stone was accidentally dropped and broke into 3 p
[#permalink]
09 Jul 2019, 23:34
09 Jul 2019, 23:34
2
Let the weight of the stone be x then,
The value of original stone would be \(x^2\)
However the stone broke into three equal pieces each piece weighing \(\frac{x}{3}\)
The value of each piece of broken stone would be \(\frac{x^2}{9}\)
There are 3 of these so there combine value would be \(\frac{3x^2}{9}\) which is \(\frac{x^2}{3}\)
Hence the value of original stone at one piece would have a higher value.
The value of original stone would be \(x^2\)
However the stone broke into three equal pieces each piece weighing \(\frac{x}{3}\)
The value of each piece of broken stone would be \(\frac{x^2}{9}\)
There are 3 of these so there combine value would be \(\frac{3x^2}{9}\) which is \(\frac{x^2}{3}\)
Hence the value of original stone at one piece would have a higher value.
Re: A precious stone was accidentally dropped and broke into 3 p
[#permalink]
10 Apr 2022, 06:42
10 Apr 2022, 06:42
Hello from the GRE Prep Club BumpBot!
Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
