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|a|/b > 1 and a+b<0

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Carcass
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|a|/b > 1 and a+b<0 [#permalink] New post   09 Aug 2018, 03:49
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\(\frac{|a|}{b} > 1\) and \(a+b<0\)

\(b \neq 0\)

Quantity A
Quantity B
a
0


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

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B
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GreenlightTestPrep
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Re: |a|/b > 1 and a+b<0 [#permalink] New post   23 Apr 2019, 06:08
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Carcass wrote:
\(\frac{|a|}{b} > 1\) and \(a+b<0\)

\(b \neq 0\)

Quantity A
Quantity B
a
0


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Kudos for R.A.E


GIVEN: \(\frac{|a|}{b} > 1\)
In other words, \(\frac{|a|}{b}\) is POSITIVE
Since |a| must be POSITIVE, we know that b must also be POSITIVE


GIVEN: \(a+b<0\)
We already know that b is POSITIVE
Since the SUM a+b is negative, we know that a is NEGATIVE

We have:
QUANTITY A: some NEGATIVE number
QUANTITY B: 0

Answer: B

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Brent
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kaziselim
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Re: |a|/b > 1 and a+b<0 [#permalink] New post   09 Aug 2018, 15:31
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Carcass wrote:
\(\frac{|a|}{b} > 1\) and \(a+b<0\)

\(b \neq 0\)

Quantity A
Quantity B
a
0


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Kudos for R.A.E



Given

\(\frac{|a|}{b} > 1\) and \(a+b<0\)

|x| is always positive.

So, b has to be positive.

but we know a + b <0. So, a has to be negative.

0 is greater than any negative value.

The best answer is B.
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Re: |a|/b > 1 and a+b<0 [#permalink] New post   12 Sep 2023, 18:51
Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: |a|/b > 1 and a+b<0 [#permalink]
12 Sep 2023, 18:51
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