OEQuote:
The new alloy X is formed from the two alloys A and B in the ratio 4 : 3. Hence, 7 parts of the alloy contains 4 parts of alloy A and 3 parts of alloy B. Let 7x ounces of alloy X contain 4x ounces of alloy A and 3x ounces of alloy B. Now, alloy A is formed of the two basic elements mentioned in the ratio 5 : 3. Hence, 4x ounces of alloy A contains 5/5+3*4x=5x/2 ounces of first basic element and 3/5+3=*4x=3x/2 ounces of the second basic
element.
Also, alloy B is formed of the two basic elements mentioned in the ratio 1 : 2. Hence, let the 3x ounces of alloy A contain 1/1+2*3x=x ounces of the first basic element and 2/2+1*3x=2x ounces of the second basic element.
Then the total compositions of the two basic elements in the 7 x ounces of alloy X would contain 5x/2 ounces (from A) + x ounces (from B) = 7x/2 ounces of first basic element, and 3/2 x (from A) + 2x (from B) = 7x/2 ounces of the second basic element. Hence, the composition of the two basic elements in alloy X is 7x/2 : 7x/2 = 1 : 1. The answer is (A).