happy1992 wrote:
A piece of twine of length t is cut into two pieces. The length of the longer piece is 2 yards greater than 3 times the length of the shorter piece which of the following of the length, in yards, of the longer piece
(A) \(\frac{(t+3)}{3}\)
(B) \(\frac{(3t+2)}{3}\)
(C) \(\frac{(t-2)}{4}\)
(D) \(\frac{(3t+4)}{4}\)
(E) \(\frac{(3t+2)}{4}\)
A piece of twine of length t is cut into two pieces. Let x = the length of the LONGER piece in yards
So, t - x = the length of the SHORTER piece in yards
The length of the longer piece is 2 yards greater than 3 times the length of the shorter piece. In other words: (longer piece) = 3(shorter piece) + 2
In other words:
x = 3(t - x) + 2 Which of the following is the length, in yards, of the longer piece?So, we must solve for x
Take:
x = 3(t - x) + 2 Expand right side: x = 3t - 3x + 2
Add 3x to both sides: 4x = 3t + 2
Divide both sides by 4 to get: \(x = \frac{3t + 2}{4}\)
Answer: E