Last visit was: 25 Nov 2024, 14:08 It is currently 25 Nov 2024, 14:08

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
User avatar
Director
Director
Joined: 16 May 2014
Posts: 592
Own Kudos [?]: 2047 [0]
Given Kudos: 0
GRE 1: Q165 V161
Send PM
User avatar
Director
Director
Joined: 16 May 2014
Posts: 592
Own Kudos [?]: 2047 [0]
Given Kudos: 0
GRE 1: Q165 V161
Send PM
avatar
Intern
Intern
Joined: 12 Nov 2018
Posts: 25
Own Kudos [?]: 15 [0]
Given Kudos: 0
Send PM
avatar
Retired Moderator
Joined: 20 Apr 2016
Posts: 1307
Own Kudos [?]: 2273 [0]
Given Kudos: 251
WE:Engineering (Energy and Utilities)
Send PM
Re: If one of the roots of the equation [#permalink]
1
JelalHossain wrote:
I did the backward calculation by taking the possible values of K. I tried to find whether the reformed equation ( in line with the value of K) gives two roots or not and the roots corroborate to the conditions or not. Eventually , whiling taking K=-1/3, It matched the conditions. Thus, I got C.
But this was too time-consuming.
Can any of you please give an easy and quicker solution ?
Regards



The solution provided above is less time consuming.

Whenever u receive a complex quadratic equation "\(ax^2 + bx + C\) " and need to find the roots, the best way is to know

1. Sum of the roots = \(-\frac{b}{a}\)

2. product of the roots = \(\frac{c}{a}\)
Prep Club for GRE Bot
Re: If one of the roots of the equation [#permalink]
Moderators:
GRE Instructor
84 posts
GRE Forum Moderator
37 posts
Moderator
1111 posts
GRE Instructor
234 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne