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\sqrt 4r=6
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22 Aug 2019, 02:55
22 Aug 2019, 02:55
00:00
Question Stats:
84% (00:18) correct
15% (00:36) wrong based on 13 sessions
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Quantity A |
Quantity B |
\(\sqrt{4r}=6\) |
\(s^2=81\) |
A)Quantity A is greater.
B)Quantity B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given
Re: \sqrt 4r=6
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22 Aug 2019, 03:58
22 Aug 2019, 03:58
Expert Reply
A) \(( \sqrt{4r} = 6 )^2\); \(4r = 36\) ; \(r = 9\)
B) \(s = \pm 9\);
\(A = B\) if we consider positive 9
\(A > B\) if we consider in quantity A 9 and in quantity B -9
D is the answer
B) \(s = \pm 9\);
\(A = B\) if we consider positive 9
\(A > B\) if we consider in quantity A 9 and in quantity B -9
D is the answer
Re: \sqrt 4r=6
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25 Aug 2019, 06:50
25 Aug 2019, 06:50
Quantity A comes out to be 9
Quantity B gives to values 9 and -9
hence answer is D
Quantity B gives to values 9 and -9
hence answer is D
