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\sqrt 4r=6

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smartchin77
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\sqrt 4r=6 [#permalink] New post   22 Aug 2019, 02:55
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Question Stats:

84% (00:18) correct 15% (00:36) wrong based on 13 sessions

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Quantity A
Quantity B
\(\sqrt{4r}=6\)
\(s^2=81\)



A)Quantity A is greater.
B)Quantity B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given
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D
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D
Carcass
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Re: \sqrt 4r=6 [#permalink] New post   22 Aug 2019, 03:58
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A) \(( \sqrt{4r} = 6 )^2\); \(4r = 36\) ; \(r = 9\)

B) \(s = \pm 9\);

\(A = B\) if we consider positive 9

\(A > B\) if we consider in quantity A 9 and in quantity B -9

D is the answer
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Darpan
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Re: \sqrt 4r=6 [#permalink] New post   25 Aug 2019, 06:50
Quantity A comes out to be 9
Quantity B gives to values 9 and -9
hence answer is D
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gmatclubot
Re: \sqrt 4r=6 [#permalink]
25 Aug 2019, 06:50
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